Vedic Mathematics 3 CD FULL(ONLY 160MB)

The Main Sutras

1. By one more than the one before.
2. All from 9 and the last from 10.
3. Vertically and Cross-wise
4. Transpose and Apply
5. If the Samuccaya is the Same it is Zero
6. If One is in Ratio the Other is Zero
7. By Addition and by Subtraction
8. By the Completion or Non-Completion
9. Differential Calculus
10. By the Deficiency
11. Specific and General
12. The Remainders by the Last Digit
13. The Ultimate and Twice the Penultimate
14. By One Less than the One Before<
15. The Product of the Sum
16. All the Multipliers

The Sub Sutras

1. Proportionately
2. The Remainder Remains Constant
3. The First by the First and the Last by the Last
4. For 7 the Multiplicand is 143
5. By Osculation
6. Lessen by the Deficiency
7. Whatever the Deficiency lessen by that amount and
8. set up the Square of the Deficiency
9. Last Totalling 10
10. Only the Last Terms
11. The Sum of the Products
12. By Alternative Elimination and Retention
13. By Mere Observation
14. The Product of the Sum is the Sum of the Products
15. On the Flag      

A  VERY SIMPLE EXAMPLE OF Vedic Math Secrets
  
Multiplying by 11

11×35= 385

(1) The five in the ones place of the answer is taken from the five in 35.

(2) The eight in the answer is the sum of 35 (3+5=8).

(3) The three in the hundreds place of the answer is taken from the three in 35.

However, if in step #2 the sum is greater than 9, the sum's left digit is added the first digit of the number multiplied by 11. For example:

11×59= 649

(1) The nine in the ones place of the answer is taken from the nine in 59.

(2) The four in the answer is the right digit in the sum of 59 (5+9=14)

(3) The six in the hundreds place of the answer is taken from the sum of the five in 59 and the digit in the tens place from the sum of 59 (5+9=14) --> (5+1=6)

The steps for multiplying a three-digit number by 11 are as follows:

11×768= 8448

(1) The 8 in the ones place of the answer is taken from the eight in 768.

(2) The 4 in the tens place of the answer is taken from the sum of 8, in the ones place of 768, and 6, in the tens place of 768 (8+6=14). As 14 is greater than 9, the 1 is carried over to step 3.

(3) The 4 in the hundreds place of the answer is taken from the sum of 6, in the tens place of 768, and 7, in the hundreds place of 768, plus the carried 1 from step 2 (6+7+1=14). As 14 is greater than 9, the 1 is carried over to step 4.

(4) The 8 in the thousandths place of the answer is taken from the sum of 7, in the hundreds place of 768, plus the carried 1 from step 3

DOWNLOAD : HOTFILE(PART1-100mb)
                       : HOTFILE(PART2-60mb)

PASSWORD : www.bigwebpages.co.nr